Understanding Poisson Distribution
The Poisson Distribution is a type of probability distribution that is used to model the number of events occurring in a fixed interval of time or space.
Discrete events: Poisson distribution applies to situations where evets are countable and they occur independently of each other, meaning that occurrence of second event is not dependent on the first event.
Fixed Interval: The distribution focusses on the number of events occurring within a specific time frame or a designated area. for example, how many customers arrived in a store per hour, or how many defects were found in a car.
Single parameter (λ): Poisson distribution is defined by a single parameter lambda (λ), which represents the average (or mean) at which events occur within a fixed interval.
Shape: When visualized Poisson distribution takes the form of a skewed bell curve, with the most likely number of events occurring around the mean (λ) and probability of observing very high or very low number of events decreasing as we move further away from the mean.
The Poisson distribution is applied in various fields to model and analyze events like:
Here is a table summarizing the key differences between Poisson, Normal, and Binomial distribution:
Feature | Normal Distribution | Binomial Distribution | Poisson Distribution |
---|---|---|---|
Data Type | Continuous | Discrete | Discrete |
Event Type | Continuous variable | Number of successes in fixed trials | Number of events in a fixed interval |
Parameters | Mean (μ) and Standard Deviation (σ) | Number of trials (n) and Probability of success (p) | Mean (λ) |
Shape | Symmetrical bell curve | Varies depending on n and p (can be symmetrical or skewed) | Skewed bell curve (most likely around the mean) |
Applications | Heights, weights, test scores, errors in measurements | Coin flips, passing/failing tests, product success/failure (limited number of trials) | Customer arrivals, accidents, defects in products, radioactive decay |
Mean-Variance Relationship | Mean (μ) ≠ Variance (σ²) | Not directly related | Mean (λ) = Variance (λ²)pen_spark |
Mean (λ): This represents the average number of occurring within a fixed interval of time or space.
Example: Imagine a Poisson distribution modeling the number of emails received in your work inbox every hour. Let’s say you typically receive an average of 96 emails per day. We can then calculate the average number of emails received per hour by dividing the daily average by the number of hours in a day:
Average emails per hour (λ) = Total daily emails / Number of hours in a day
λ = 96 emails / 24 hours
λ = 4 emails per hour
Therefore, the mean of the Poisson distribution in this scenario is 4. This signifies that, on average, you receive 4 emails per hour.
Standard Deviation (σ): This represents the data spread around the mean, Interestingly, in Poisson distribution, the variance (σ²) is equal to the mean (λ). Therefore, the standard deviation (σ) is simply the square root of the mean.
σ = √λ
Example: Imagine a Poisson distribution modeling the number of customer arrivals at a store in a given hour (fixed interval). If the average arrival rate (mean) is 10 customers per hour which is represented as λ = 10, then the variance (σ²) would also be 10, and the standard deviation (σ) would be:
σ = √λ = √10 ≈ 3.16 (rounded to two decimal places)
This explains that in this scenario, the number of customer arrivals is likely to be within 3.16 customers (one standard deviation) of the average arrival rate of 10 customers per hour.
The Poisson probability can be calculated using the below formula, it allows you to calculate the probability (P(X = x)) of getting a specific number of events (x) within a given interval, considering the average number of events (λ) expected during that interval.
The formula is:
P(X = x) = (e^-λ * λ^x) / x!
where:
Here’s how to use the formula:
Example: Imagine you’re analyzing customer complaints at a call center. The average number of complaints per hour is 3 (λ = 3). You want to know the probability of receiving exactly 2 complaints in an hour (x = 2).
P(X = 2) = (e^-3 * 3^2) / 2!
e^-3 = 0.049 (approximately)
3^2 = 9
2! = 2
P(X = 2) = (0.049 * 9) / 2
P(X = 2) ≈ 0.221
Therefore, the probability of receiving exactly 2 complaints in an hour is approximately 0.221 or 22.1%.
We can also use tools like Python or Excel to calculate the same.
Cumulative v/s Probability
Cumulative Poisson Probability (P(X <= x):
Poisson Probability Mass Function (P(X = x):
We hope you found the information helpful! If you learned something valuable, consider sharing it with your friends, family, and social networks.
Reference: Khan Academy, Wikipedia
Also Read:
Hi, I am Vishal Jaiswal, I have about a decade of experience of working in MNCs like Genpact, Savista, Ingenious. Currently i am working in EXL as a senior quality analyst. Using my writing skills i want to share the experience i have gained and help as many as i can.
SQL Interview Question at Zomato: These questions were recently asked in interview at Zomato, you…
Introduction: SQL Indexing and Query Optimization SQL indexing is a critical concept that can drastically…
This article is about the SQL Interview Questions asked by Walmart for their Data Analyst…
You must be able to answer these SQL Interview Questions if you are applying for…
This article tackles common SQL Interview Questions asked by EY, offering detailed solutions and explanations…
1164. Product Price at a Given Date: Learn how to track and select price from…